SOLUTION: A particular metal ally A has 20% iron and another alloy B contains 60% iron. How many kilograms of each alloy should be combined to create 80 kg of 52% iron alloy

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Question 748663: A particular metal ally A has 20% iron and another alloy B contains 60% iron. How many kilograms of each alloy should be combined to create 80 kg of 52% iron alloy
Found 2 solutions by stanbon, Megan-notamathgeekatall:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A particular metal alloy A has 20% iron and another alloy B contains 60% iron. How many kilograms of each alloy should be combined to create 80 kg of 52% iron alloy
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iron + iron = iron
0.20x + 0.60(80-x) = 0.52(80)
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20x + 60*80 - 60x = 52*80
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-40x = -8*80
x = (1/5)80
x = 16 kg (amt. of 20% alloy needed)
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80-x = 64 kg (amt. of 60% alloy needed)
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Cheers,
Stan H.
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Answer by Megan-notamathgeekatall(1) (Show Source):
You can put this solution on YOUR website!

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iron + iron = iron
0.20x + 0.60(80-x) = 0.52(80)
---------------------------
20x + 60*80 - 60x = 52*80
-----
-40x = -8*80
x = (1/5)80
x = 16 kg (amt. of 20% alloy needed)
-----
80-x = 64 kg (amt. of 60% alloy needed)

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .
X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 8/4 = 2.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 8/2 = 4.
Slope is -4/2 = -2.
Equation in slope-intercept form: y=-2*x+4.