SOLUTION: Wilma went to the local market and bought 3 lemons and 5 oranges for $2.40.The same day and for the same price ,Fran bought 4 lemons and 7 oranges for $3.31.What was the prices per

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Wilma went to the local market and bought 3 lemons and 5 oranges for $2.40.The same day and for the same price ,Fran bought 4 lemons and 7 oranges for $3.31.What was the prices per      Log On

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Question 744992: Wilma went to the local market and bought 3 lemons and 5 oranges for $2.40.The same day and for the same price ,Fran bought 4 lemons and 7 oranges for $3.31.What was the prices per lemon and the price per orange?
Answer is $o.25 per lemon and $.33 per orange

Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = price of a lemon
Let +b+ = price of an orange
given:
(1) +3a+%2B+5b+=+240+ ( in cents )
(2) +4a+%2B+7b+=+331+ ( in cents )
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Multiply both sides of (1) by 4
and both sides of (2) by 3
Then subtract (1) from (2)
(2) +12a+%2B+21b+=+993+
(1) +-12a+-+20b+=+960+
+b+=+33+
and
(1) +3a+%2B+5%2A33+=+240+
(1) +3a+=+240+-+165+
(1) +3a+=+75+
(1) +a+=+25+
25 cents /lemon and
33 cents/orange


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Wilma went to the local market and bought 3 lemons and 5 oranges for $2.40.The same day and for the same price ,Fran bought 4 lemons and 7 oranges for $3.31.What was the prices per lemon and the price per orange?
Answer is $o.25 per lemon and $.33 per orange
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Equations:
3L + 5R = 240 cents
4L + 7R = 331 cents
----------
Multiply thru top eq. by 4:
Multiply thru bottom eq. by 3:
------
12L + 20R = 960
12L + 21R = 993
------
Substract and solve for "O":
R = 33 cents (price of one orange)
----
Solve for "L":
3L + 5R = 240
3L + 5*33 = 240
3L + 165 = 240
3L = 75
L = 25 cents (price of one lemon)
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Cheers,
Stan H.
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