SOLUTION: in a cricket match bye runs were double of the no-balls,the remaining score was greater by six than twelve times the number of bye-runs.if the total score was 276.how were the runs

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Question 741217: in a cricket match bye runs were double of the no-balls,the remaining score was greater by six than twelve times the number of bye-runs.if the total score was 276.how were the runs obtained?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
No balls----------x
byes = 2x
total runs = 276
remaining runs = (276-3x)=12*2x+6

276-3x=24x+6
27x=270
x=10
No ball
s = 10
Byes = 20
Runs = 246