SOLUTION: how many liters of pure alcohol must be mixed with 40 liters of a 25% alcohol solution to get 50% mixture
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Question 738820
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how many liters of pure alcohol must be mixed with 40 liters of a 25% alcohol solution to get 50% mixture
Answer by
richwmiller(17219)
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40*.25+x=.5(40+x)
x=20 liters