SOLUTION: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is neede
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is neede
Log On
Question 732388: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is needed to make 50 pounds of the mixture? Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! This problem fits a very general two-part mixture situation. Here will be the beginning of a purely symbolic solution.
L = $2.50/pound for the fruit
H = $7.00/pound for the nuts
T = $4.30/pound for the mixture
M = 50 pounds, quantity of the mixture
u = unknown pounds of fruit
v = unknown pounds of nuts
Objective is to solve for u and v. A system of equations is necessary.
and
More than one way to start this solution process from here, but you could begin by doing a few operations on the T equation. It may be transformed to a linear equation of the two variables in standard for or general form, whichever you wish. Anyhow, you have two linear equations in two unknowns. Solve!
Once solved for u and v, just substitute your given values to compute u and v.
(