SOLUTION: A grocer has two kinds of loose tea. One is worth $5 per pound and the other is worth $7 per pound.
She mixes some of each kind of tea together to get a total of 50 pounds of a
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A grocer has two kinds of loose tea. One is worth $5 per pound and the other is worth $7 per pound.
She mixes some of each kind of tea together to get a total of 50 pounds of a
Log On
Question 732008: A grocer has two kinds of loose tea. One is worth $5 per pound and the other is worth $7 per pound.
She mixes some of each kind of tea together to get a total of 50 pounds of a mixed tea worth a total of $314.00.
Let
x = number of pounds of $5/pound tea in the mixture
y = number of pounds of $7/pound tea in the mixture
Use a system of equations that describes this situation to figure out how much of each kind of tea is in the mixture. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! x = number of pounds of $5/pound tea in the mixture
y = number of pounds of $7/pound tea in the mixture
------------
(1)
(2)
--------------------
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
18 pounds of $5/pound tea are needed
32 pounds of $7/pound tea are needed