SOLUTION: twenty liters of an 87.5% alcohol solution is obtained by mixing a 95% solution with 70% solution. How many liters of each solution must be used to obtain the desired mixture?

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Question 730719: twenty liters of an 87.5% alcohol solution is obtained by mixing a 95% solution with 70% solution. How many liters of each solution must be used to obtain the desired mixture?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
M liters of an T% alcohol solution is obtained by mixing a H% solution with L% solution. How many liters as u and v of each solution must be used to obtain the desired mixture?

highlight%28%28Lu%2BHv%29%2FM=T%29 AND highlight%28u%2Bv=M%29.
Solve for u and v for the system.

You could begin with transforming the rational equation.
Lu%2BHv=TM, and try solving for one of the variables in the M equation and substitute into the transformed rational equation, as an example,
v=M-u,
then
Lu%2BH%28M-u%29=TM
Lu%2BHM-Hu=TM
Lu-Hu%2BHM=TM
.
which allows you to obtain a formula for u.
.
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