SOLUTION: ellen wants to mix candy worth 1.09$ per pound with candy worth $3.32 per pound to form 25 pounds of a mixture worth $2.43 per pound. how many pounds of the expensive candy should

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Question 730110: ellen wants to mix candy worth 1.09$ per pound with candy worth $3.32 per pound to form 25 pounds of a mixture worth $2.43 per pound. how many pounds of the expensive candy should she use?
Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
price ---------------- quantity
Candy type I 3.32 ---------------- x pounds
Candy type II 1.09 ------ 25 - x pounds
Mixture 2.43 ---------------- 25
25
3.32 x + 1.09 ( 25 - x ) = 60.75
3.32 x + 27.25 - 1.09 x = 60.75
3.32 x - 1.09 x = 60.75 - -27.25
2.23 x = 33.5
/ 2.23
x = 15.02 pounds 3.32 Candy type I
9.98 pounds 2.43 Candy type II

m.ananth@hotmail.ca

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = pounds of $1.09 candy needed
Let +b+ = pounds of $3.32 candy needed
given:
(1) +a+%2B+b+=+25+
(2) +%28+1.09a+%2B+3.32b+%29+%2F+25+=+2.43+
---------------------------------
(2) +109a+%2B+332b+=+243%2A25+
(2) +109a+%2B+332b+=+6075+
--------------------------
Multiply both sides of (1) by +109+
and subtract (1) from (2)
(2) +109a+%2B+332b+=+6075+
(1) +-109a+-+109b+=+-2725+
+223b+=+3350+
+b+=+15.022+
15.022 pounds of $3.32 candy is needed
check:
(1) +a+%2B+b+=+25+
(1) +a+%2B+15.022+=+25+
(1) +a++=+9.978+
and
(2) +%28+1.09a+%2B+3.32b+%29+%2F+25+=+2.43+
(2) +%28+1.09%2A9.978+%2B+3.32%2A15.022+%29+%2F+25+=+2.43+
(2) +10.876+%2B+49.873+=+2.43%2A25+
(2) +60.749+=+60.75+
Close enough