SOLUTION: Pure acid is to be added to a 10% acid solution to obtain 90l of 56% solution. What amounts should be used?

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Question 729919: Pure acid is to be added to a 10% acid solution to obtain 90l of 56% solution. What amounts should be used?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Pure acid is to be added to a 10% acid solution to obtain 90l of 56% solution. What amounts should be used?
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Equation:
acid + acid = acid
x + 0.10(90L-x) = 0.56*90
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100x + 10*90L - 10x = 56*90
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90x = 46*90
x = 46 L (amt. of pure acid to add)
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Cheers,
Stan H.
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