SOLUTION: How many liters of 20% and 60% acids must be mixed in order to make 12 liters of a 55% acid solution

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Question 728099: How many liters of 20% and 60% acids must be mixed in order to make 12 liters of a 55% acid solution
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many liters of 20% and 60% acids must be mixed in order to make 12 liters of a 55% acid solution
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Equation:
acid + acid = acid
0.20x + 0.60(12-x) = 0.55*12
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20x + 60*12-60x = 55*12
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-40x = -5*12
x = 12/8
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x = 3/2 liters (amt. of 20% solution needed)
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Cheers,
Stan H.
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