SOLUTION: a 20 liter container is filled with pure acid. five liters of the mixture are drawn off and replaced with water and so on until 5 drawing and 5 replacements have been made. find th

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Question 727984: a 20 liter container is filled with pure acid. five liters of the mixture are drawn off and replaced with water and so on until 5 drawing and 5 replacements have been made. find the amount of acid in the final mixture
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
After 1st replacement,
there is +20+-+5+=+15+ liters of acid in 20 liters of solution
-------------------
After 2nd replacement
There is +5%2A%28+15%2F20+%29+=+15%2F4+ liters of acid removed
There is +15+-+15%2F4+=+45%2F4+ liters of acid left
+11.25+ liters left
--------------------
After 3rd replacement
There is +5%2A%28+%28+45%2F4%29%2F20+%29++=+5%2A%2845%2F80%29+
+45%2F16+ liters of acid removed
There is +45%2F4+-+45%2F16+=+135%2F16+ liters of acid left
+8.4375+ liters left
---------------------
After 4th replacement
There is +5%2A%28+%28+135%2F16+%29+%2F20+%29+=+135%2F64+ liters
of acid removed
There is +135%2F16+-+135%2F64+=+405%2F64+ liters of acid left
+6.328125+ liters left
-----------------------
After 5th replacement
There is +5%2A%28+%28+405%2F64+%29+%2F20+%29+=+405%2F256+ liters of acid removed
There is +405%2F64+-+405%2F256+=+1215%2F256+ liters of acid left
-------------------------
+1215%2F256+=+4.7461+ liters of acid left
Hope I got it!