SOLUTION: Pure acid is to be added to a 10% acid solution to obtain 90L of 55% solution. What amounts of each should be used? A)How many liters of 100% pure acid should be used to make the s

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Question 727784: Pure acid is to be added to a 10% acid solution to obtain 90L of 55% solution. What amounts of each should be used? A)How many liters of 100% pure acid should be used to make the solution? B)How many liters of the 10% solution should be in the mixture?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
VARIABLES
u = how much 10% acid to use, unknown
v = how much 100% acid to use, unknown
M = volume of resulting solution, 90L
L = percent of low concentration acid material to use, 10%
T = intended percent concentration of acid in the resulting solution, 55%

EQUATIONS
highlight%28%28Lu%2Bv%29%2FM=T%29 AND highlight%28u%2Bv=M%29

PROCESS
Those are two equations with two unknowns. Both equations are linear in u and v. Solve for u and v. Substitute known and given values to compute u and v.