SOLUTION: A trucking company has 1000 liters of coolant. The coolant is 30% antifreeze. How much water should be added to make the mixture 25% antifreeze? I've tried a porportion; {{ 100

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Question 725315: A trucking company has 1000 liters of coolant. The coolant is 30% antifreeze. How much water should be added to make the mixture 25% antifreeze?
I've tried a porportion; {{ 1000/b=25/100}} then I cross multiplied to get, 25b=100,000. After that I divided both sides to get b=4,000 liters of water. I'm not positive that is the answer.
Thank you for your help.
Found 2 solutions by josmiceli, richwmiller:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = liters of water to be added
+.3%2A1000+=+300+ liters of antifreeze in the coolant
The amount of antifreeze does not change in this problem
+300+%2F+%28+1000+%2B+w+%29+=+.25+
+300+=+.25%2A%28+1000+%2B+w+%29+
+300+=+250+%2B+.25w+
+.25w+=+50+
+w+=+200+
200 liters of water should be added
+300+%2F+%28+1000+%2B+w+%29+=+.25+
+300+%2F+%28+1000+%2B+200+%29+=+.25+
+300+%2F+1200+=+.25+
+.25+=+.25+
OK

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
from perspective of the water.
70*1000+x=.75(1000+x)
x=200 liters of water
add 200 liters of water
or
from view of antifreeze
.3*1000=.25(1000+x)
x=200 liters of water
add 200 liters of water