Question 723331: A car radiator is filled with 4 gal of a 30% antifreeze solution. How much pure antifreeze must be added to have a 75% antifreeze solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A car radiator is filled with 4 gal of a 30% antifreeze solution. How much pure antifreeze must be added to have a 75% antifreeze solution?
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Equation:
anti + anti = anti
0.30*4 + 1.00*x = 0.75(4+x)
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Multiply thru by 100 to get:
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30*4 + 100x = 75*4 + 75x
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25x = 45*4
x = (9/5)4
x = 36/5
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x = 7 1/5 gallons (amt. of pure antifreeze to add)
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Cheers,
Stan H.
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