SOLUTION: A pharmacist needs to obtain a 60% alcohol solution. How many ounces of a 30% alcohol solutu=ion must be mixed with 50 ounces of an 80% alcohol solution to obtain a 60% alcohol sol

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Question 713985: A pharmacist needs to obtain a 60% alcohol solution. How many ounces of a 30% alcohol solutu=ion must be mixed with 50 ounces of an 80% alcohol solution to obtain a 60% alcohol solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ounces of 30% solution needed
+.3x+ = ounces of alcohol in 30% solution
+.8%2A50+=+40+ ounces of alcohol in 80% solution
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+%28+.3x+%2B+40+%29+%2F+%28+x+%2B+50+%29+=+.6+
+.3x+%2B+40+=+.6%2A%28+x+%2B+50+%29+
+.3x+%2B+40+=+.6x+%2B+30+
+.3x+=+40+-+30+
+.3x+=+10+
+x+=+33.333+
The pharmacist needs 33 1/3 ounces of 30% solution
check:
+%28+.3x+%2B+40+%29+%2F+%28+x+%2B+50+%29+=+.6+
+%28+.3%2A33.333+%2B+40+%29+%2F+%28+33.333+%2B+50+%29+=+.6+
+%28+10+%2B+40%29+%2F+83.333+=+.6+
+50+=+.6%2A83.333+
+50+=+50+
OK