SOLUTION: How many ounces of a 35% alcohol solution must be mixed with 15 ounces of a 40% alcohol solution to make a 38% alcohol solution?

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Question 713286: How many ounces of a 35% alcohol solution must be mixed with 15 ounces of a 40% alcohol solution to make a 38% alcohol solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
That is an example of the general question:
How much of a higher concentration material must be mixed with some quantity of a lower concentration material to make a mixture of some intermediate value concentration?

L=35%, concentration of lower strength material
H=40%, concentration of higher strength matarial
T=38%, target concentration of mixture wanted
u= unknown, ounces of lower strength stuff to add
v=15 ounces, ounces of available higher strength stuff to be used.

The General Problem can be solved all in symbols:
%28Lu%2BHv%29%2F%28u%2Bv%29=T, we solve for u, the only unknown here.
Lu%2BHv=T%28u%2Bv%29
Lu%2BHv=Tu%2BTv
Lu-Tu=-Hv%2BTv
%28L-T%29u=%28T-H%29v
u=v%28T-H%29%2F%28L-T%29, knowing that those differences are actually both negative we can do
highlight%28u=v%28H-T%29%2F%28T-L%29%29

Now just substitute the given values to find u, the ounces of 35% alcohol.