SOLUTION: What quantity of a 60% acid solution must be mixed with a 35% solution to produce 600 mL of a 45% solution?

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Question 712509: What quantity of a 60% acid solution must be mixed with a 35% solution to produce 600 mL of a 45% solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assign some variables to everyting.
M=600 ml. result solution
u= volume of 35% solution
v = volume of 60% solution
T = 45% solution wanted
L = 35%
H = 60%
You want to find u and v.

The concentration equation symbolically can begin as %28Lu%2BHv%29%2F%28u%2Bv%29=T.
Also fact is u+v=M. Solve this simpler one for v, to have v=M-u; substitute this into the rational equation, solve for u, and you will have, after algebraic steps:
highlight%28u=M%28H-T%29%2F%28H-L%29%29, substitute the given values to find value for u, and then go back to highlight%28v=M-u%29 and get the value for v.

SUBSTITUTING VALUES TO GET u:
%2860-45%29%2A600%2F%2860-35%29=u,....