SOLUTION: Twenty ounces of pure silver are added to 70 oz of a silver alloy that is 10% silver. What is the percent concentration of the resulting alloy?

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Question 711594: Twenty ounces of pure silver are added to 70 oz of a silver alloy that is 10% silver. What is the percent concentration of the resulting alloy?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Pure silver is 100% silver.
There are high percent silver and lower percent silver and the mixture will make some intermediate percent silver, T.
T = the resulting % silver Unknown but will be found
H = 100, the pure silver 100%
L = 10, the 10% silver concentration
x = 70 ounces of 10% silver
y = 20 ounces of 100% silver.

Objective is find T.
Amount of silver = x*L+y*H
Amount of alloy = x+y

T=%28x%2AL%2By%2AH%29%2F%28x%2By%29

Use the given values:
T=%2870%2A10%2B20%2A100%29%2F%2870%2B20%29
T=30, so alloy resulting is 30% silver.