SOLUTION: There is 20 gallons of 20% o.j. How many gallons must be mixed with 80% o.j. to make the mixture have 50% o.j. drink?

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Question 710162: There is 20 gallons of 20% o.j. How many gallons must be mixed with 80% o.j. to make the mixture have 50% o.j. drink?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = gallons of 80% OJ needed
+.8x+ = gallons of OJ in 80% OJ
+.2%2A20+=+4+ gallons of OJ in 20% OJ
---------------------------------
+%28+.8x+%2B+4+%29+%2F+%28+x+%2B+20+%29+=+.5+
+.8x+%2B+4+=+.5%2A%28+x+%2B+20+%29+
+.8x+%2B+4+=+.5x+%2B+10+
+.3x+=+6+
+x+=+20+
20 gallons of 80% OJ is needed
check:
+%28+.8%2A20+%2B+4+%29+%2F+%28+20+%2B+20+%29+=+.5+
+%28+16+%2B+4+%29+%2F+40+=+.5+
+20%2F40+=+.5+
+.5+=+.5+
OK