SOLUTION: How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol solution?

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Question 709609: How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol solution?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol solution?
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Equation:
alc + alc = alc
0.20x + 0.75(32-x) = 0.40*32
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20x + 75*32 - 75x = 40*32
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-55x = -35*32
x = (7/11)32
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x = 20.36 liters (amt. of 20% solution needed)
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32-x = 32-20.36 = 11.64 liters (amt. of 75% solution needed)
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Cheers,
Stan H.
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