SOLUTION: How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze?

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Question 707365: How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze?
Answer by nshah11(47) About Me  (Show Source):
You can put this solution on YOUR website!
(0.9(x) + 60(1/10))/(60 + x) = 0.8
48 + 0.8x = 0.9x + 6
0.1x = 42
x = 420 gallons