SOLUTION: A chemist prepared 100 mL of 15% saline solution by using a 20% solution, an 18% solution, and 40 mL of a 10% solution. How much of the 20% and 18% were used? Please include an equ

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Question 704921: A chemist prepared 100 mL of 15% saline solution by using a 20% solution, an 18% solution, and 40 mL of a 10% solution. How much of the 20% and 18% were used? Please include an equation for setting this problem up if possible. Thanks!
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x is how much 18% saline
y is how much 20% saline

The system to solve:
%28x%2A0.18%2By%2A0.20%2B40%2A0.10%29%2F%28100%29=0.15
x%2By%2B40=100

Note that you may work the rational equation into
18x+20y+40*10=100*15
18x+20y+400=1500
9x%2B10y%2B200=750