SOLUTION: Please help me!!!!
A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 ch
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A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 ch
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Question 704816: Please help me!!!!
A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix together with the $4.55 cheese to get a 45-pound block mixture that sells for $4.05 a pound?
You can put this solution on YOUR website! A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix together with the $4.55 cheese to get a 45-pound block mixture that sells for $4.05 a pound?
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Equations:
a + b = 45 lbs
375a + 455b = 405*45
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455a + 455b = 455*45
375a + 455b = 405*45
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80a = 50*45
a = (5/8)45
a = 28.125 lbs (amt. of $3.75 cheese needed)
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Cheers,
Stan H.
You can put this solution on YOUR website! Let A = pounds of cheese that costs $3.75/pound
Let B = pounds of cheese that costs $4.55/pound
Equation 1: (A 45 pound block of mixed cheese)
Equation 2: (The cost per pound of the mixed cheese block)
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Solve Equation 1 for one of the variables.
Equation 1:
Now plug (45 - B) into Equation 2 for A
Equation 2:
Multiply the 3.75 trough and simplify the equation
Multiply both sides by 45
Combine like terms
Subtract 168.75 from both sides
Divide both sides by 0.8
Now plug 16.875 into equation 1 for B
Equation 1:
You can put this solution on YOUR website! Let = pounds of the $3.75/pound cheese needed
Let = pounds of the $4.55/pound cheese needed
given:
(1)
(2)
--------------------------------
(2)
(2)
(2)
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
(1)
(1)
28.125 pounds of the $3.75/pound cheese is needed
16.875 pounds of the $4.55/pound cheese is needed
check answer:
(2)
(2)
(2)
(2)
(2)
OK
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