Question 696133: Ten gallons of 30% acid solution is obtained by mixing a 20% solution with a 50% solutions.How much of each solution must be used? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = gallons of 20% solution needed
Let = gallons of 50% solution needed
given:
(1)
(2)
--------------------------
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
(1)
(1)
3 and 1/3 gallons of 20% solution are needed
6 and 2/3 gallons of 50% solution are needed
check answer:
(2)
(2)
(2)
(2)
(2)
(2)
OK
