SOLUTION: How much 5% acid must be mixed with 25% acid to obtain 500 ml of 7% acid

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Question 690956: How much 5% acid must be mixed with 25% acid to obtain 500 ml of 7% acid
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How much 5% acid must be mixed with 25% acid to obtain 500 ml of 7% acid
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Equation:
acid + acid = acid
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0.05x + 0.25(500-x) = 0.07*500
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Multiply thru by 100 to get:
5x + 25*500 - 25x = 7*500
-20x = -18*500
x = 18*25
x = 450 ml (amt of 5% solution needed)
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500 -x = 50 ml (amt. of 25% solution needed)
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Cheers,
Stan H.
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