SOLUTION: Bob needs to buy 5 pounds of candy. one kind costs 1.75 per pound and the second kind costs 2.35 per pound. How much of each will he need if he spends 10.00?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Bob needs to buy 5 pounds of candy. one kind costs 1.75 per pound and the second kind costs 2.35 per pound. How much of each will he need if he spends 10.00?
Log On
Question 68112: Bob needs to buy 5 pounds of candy. one kind costs 1.75 per pound and the second kind costs 2.35 per pound. How much of each will he need if he spends 10.00? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Bob needs to buy 5 pounds of candy. one kind costs 1.75 per pound and the second kind costs 2.35 per pound. How much of each will he need if he spends 10.00?
:
A mixture problem;
:
We can say that the resulting mixture is worth 10/5 = 2.00/lb
:
let x = amt of 1.75 /lb candy;
let (5-x) = 2.35 /lb candy
:
1.75x + 2.35(5-x) = 2(5)
:
1.75x + 11.75 - 2.35x = 10
1.75x - 2.35x = 10 - 11.75
-.6x = -1.75
x = -1.75/-.6
x = 2.92 lb of the $1.75 candy
:
5 - 2.92 = 2.08 lb of the $2.35 candy
:
:
Check:
1.75(2.92) + 2.35(2.08) =
5.11 + 4.89 = $10
