SOLUTION: The perimeter of a rectangle is 92m If the width were doubled and the length were increased by 24m, then the perimeter would be 182m. What are the dimensions? w 18 L 23 W 25 L

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: The perimeter of a rectangle is 92m If the width were doubled and the length were increased by 24m, then the perimeter would be 182m. What are the dimensions? w 18 L 23 W 25 L       Log On

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Question 678285: The perimeter of a rectangle is 92m If the width were doubled and the length were increased by 24m, then the perimeter would be 182m. What are the dimensions?
w 18 L 23
W 25 L 21
W 21 L 25
W 23 L 23

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is P=92m
=> 92m=2L%2B2W....eq. 1
If the width W were doubled and the length L were increased by 24m, then the perimeter would be P=182m

=>182m=2%28L%2B24m%29%2B2%2A2W....eq. 2

solve the system:
92m=2L%2B2W....eq. 1
182m=2%28L%2B24m%29%2B2%2A2W....eq. 2
_______________________________
92m=2L%2B2W....eq. 1 ...solve for L
92m=2L%2B2W....both sides divide by 2
92m%2F2=2L%2F2%2B2W%2F2
46m=L%2BW
L=46m-W.....substitute in eq. 2

182m=2%28L%2B24m%29%2B2%2A2W....eq. 2.first both sides divide by 2
91m=%28L%2B24m%29%2B2W
91m=%28L%2B24m%29%2B2W.......substitute L
91m=%2846m-W%2B24m%29%2B2W....solve for W
91m=70m-W%2B2W
91m=70m%2BW
W=91m-70m
highlight%28W=21m%29

now find L

L=46m-W
L=46m-21m
highlight%28L=25m%29

so, your answer is:W 21 L 25