Question 678166: how many liters of a 10 alcohol solution must be mixed with 80 liters of a 70% solution to get a 30% solution? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! how many liters of a 10 alcohol solution must be mixed with 80 liters of a 70% solution to get a 30% solution?
.
Let x = amount (liters) of 10% alcohol added
then
.10x + .70(80) = .30(x+80)
.10x + 56 = .30x+24
56 = .20x+24
32 = .20x
32/.20 = x
160 liters = x
