SOLUTION: how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 670085: how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper
-----
Equation:
active + active = active
0.30x + 0.70*600 = 0.50(x+600)
---------
30x + 70*600 = 50x + 50*600
20x = 20*600
x = 600 ounces (amt. of 30% alloy needed)
======================
Cheers,
Stan H.