SOLUTION: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%. a metallurgist has one alloy con

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Question 668879: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%. use your model to calculate the mixture needed for 50lbs of 40% copper.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
Create a model to determine how many pounds of each alloy to mix to achieve
a given weight and copper percentagehighlight%28P%29: .70x%2B+.20y=+P%28x%2By%29
calculate the mixture needed for 50lbs of 40% copper.
.70x+%2B+.20%2850-x%29+=+.40%2A50 y+=+%2850-x%29
.50x = .20*50
x = 20lbs 70% and 30lbs 20%