SOLUTION: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
a metallurgist has one alloy con
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
a metallurgist has one alloy con
Log On
Question 668879: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%. use your model to calculate the mixture needed for 50lbs of 40% copper. Answer by ewatrrr(24785) (Show Source):
Hi,
a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
Create a model to determine how many pounds of each alloy to mix to achieve
a given weight and copper percentage:
calculate the mixture needed for 50lbs of 40% copper.
.50x = .20*50
x = 20lbs 70% and 30lbs 20%