SOLUTION: How many liters (L) of a 20% solution must be mixed with 40 L of a 80% solution to get a 50% solution?
My teacher wants us to make 2 equations. We solve them by plugging them in
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My teacher wants us to make 2 equations. We solve them by plugging them in
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Question 668647: How many liters (L) of a 20% solution must be mixed with 40 L of a 80% solution to get a 50% solution?
My teacher wants us to make 2 equations. We solve them by plugging them into the calculator. I just need to know how to get 2 equations out of this. Thank you so much! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters (L) of a 20% solution must be mixed with 40 L of a 80% solution to get a 50% solution?
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Quantity Equation: x + 40 = y
Ingrediant Eq::: 0.20x + 0.80*40 = 0.50y
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Rearrange and multiply the 1st equation by 20
Rearrange and multiply the 2nd equation by 100
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20x - 20y = -800
20x - 50y = -3200
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Cheers,
Stan H.
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