SOLUTION: A jar filled with change is holding $5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of $4.55. How many
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A jar filled with change is holding $5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of $4.55. How many
Log On
Question 664309: A jar filled with change is holding $5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of $4.55. How many of each type of coin was there originally? Set up a system of 3 equations and solve to answer this question. Show your work! Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! 18 nickels=========.90
15 quarters========$3.75
8 dimes============.80
you have a total of ==41 coins==
take the nickels out from the total of $5.45,you have $4.55
(