Question 663414: a father is three times as old as his son. after twelve years, his age will be twice as that of his son then. find their present ages. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a father is three times as old as his son. after twelve years, his age will be twice as that of his son then. find their present ages.
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Equations:
f = 3s
f+12 = 2(s+12)
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Substitute for "f" and solve for "s":
3s+12 = 2s+24
s = 12 yrs (the son's age)
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Solve for "f":
f = 3s
f = 3*12 = 36 yrs (the father's age)
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Cheers,
Stan H.
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