SOLUTION: A radiator contains 5 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze? (Ro

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A radiator contains 5 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze? (Ro      Log On

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Question 662306: A radiator contains 5 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze? (Round your answer to two decimal places.)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = quarts of fluid to be drained
and replaced with pure antifreeze
+.3%2A5+=+1.5+ quarts of antifreeze originally
------------
+%28+1.5+-+.3x+%2B+x+%29+%2F+5+=++.6+
Note that you started with 5 quarts and
ended with 5 quarts
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+%28+1.5+%2B+.7x+%29+%2F+5+=+.6+
+1.5+%2B+.7x+=+.6%2A5+
+1.5+%2B+.7x+=+3+
+.7x+=+1.5+
+x+=+2.14+
2.14 quarts of fluid should be drained
and replaced with pure antifreeze