SOLUTION: Tickets for a school play sold for $7.50 for each adult and $3 for each child. The total reciepts for 113 tickets sold were $663. Find the number of adult tickets sold!
Please g
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Tickets for a school play sold for $7.50 for each adult and $3 for each child. The total reciepts for 113 tickets sold were $663. Find the number of adult tickets sold!
Please g
Log On
Question 652410: Tickets for a school play sold for $7.50 for each adult and $3 for each child. The total reciepts for 113 tickets sold were $663. Find the number of adult tickets sold!
Please get back to me as soon as you can! Thank you! Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
Tickets for a school play sold for $7.50 for each adult and $3 for each child. The total reciepts for 113 tickets sold were $663. Find the number of adult tickets sold!
Please get back to me as soon as you can! Thank you!
Let amount of adults who attended be A
Then amount of children who attended = 113 - A
Since an adult and a child's ticket cost $7.5, and $3, respectively, then:
7.5A + 3(113 - A) = 663
7.5A + 339 - 3A = 663
7.5A - 3A = 663 - 339
4.5A = 324
A, or amount of adults who attended = , or
Since 113 tickets were sold, and since 72 adults attended, then amount of children who attended = 113 - 72, or
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com