SOLUTION: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get a 40% solution?
Here is the equation that I tried to make out of it.
.3x ti
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Here is the equation that I tried to make out of it.
.3x ti
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Question 648378: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get a 40% solution?
Here is the equation that I tried to make out of it.
.3x times .9(80)= .40
It seems so simple but I keep screwing it up. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get a 40% solution?
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You have 80 l of 90%
You add x liters of 30%
80*90 + x*30 = (80 + x)*40
Solve for x
