SOLUTION: A solution of 61% bleach is to be mixed with a solution of 27% bleach to make 68 gallons of a 44% solution. How many gallons of each should be used?
Question 636254: A solution of 61% bleach is to be mixed with a solution of 27% bleach to make 68 gallons of a 44% solution. How many gallons of each should be used?
Found 3 solutions by Maths68, ankor@dixie-net.com, Alan3354:Answer by Maths68(1474) (Show Source):
(Amount of Solution A)(Concentration of Solution A)+(Amount of Solution B)(Concentration of Solution B)=(Amount of Mixture)(Concentration of Mixture)
(x)(0.61)+(68-x)(0.27)=(68)(0.44)
0.61x+18.36-0.27x=29.92
0.34x+18.36=29.92
0.34x=29.92-18.36
0.34x=11.56
0.34x/0.34=11.56/0.34
x=34
You can put this solution on YOUR website! A solution of 61% bleach is to be mixed with a solution of 27% bleach
to make 68 gallons of a 44% solution.
How many gallons of each should be used?
:
Let x = amt of 61% bleach required
the resulting mixture is to be 68 gal, therefore:
(68-x) = amt of 27% solution required
:
A typical mixture equation
:
.61x + .27(68-x) = .44(68)
:
.61x + 18.36 - .27x = 29.92
.61x - .27x = 29.92 - 18.36
.34x = 11.56
x = 11.56/.34
x = 34 gal of 61% solution
and
68 - 34 = 34 gal of 27% solution
You can put this solution on YOUR website! A solution of 61% bleach is to be mixed with a solution of 27% bleach to make 68 gallons of a 44% solution. How many gallons of each should be used?
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44 is the average of 61 & 27, so it's equal amounts.