SOLUTION: A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

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Question 631789: A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=90;
.38x+.47y=.42*90
x=50 of the 38% y=40 of the 47%

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available.

 Set Up on ALL mixture problems is to have the same amount of the key ingredient on both sides of the EQ

Let x represent the amoount of 47% solution

  .47x+%2B+.38%2890-x%29+=+.42%2A90   | Solve for x, multiplying EQ thru by 100 first, if you like