You can put this solution on YOUR website! The product of two consecutive integers is 5 less than 5 times their sum. Find the integers
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let x=first digit
x+1=consecutive digit
..
x(x+1)=5(x+x+1)-5
x^2+x=10x+5-5
x^2-9x=0
x(x-9)=0
x=0 (reject, not a solution)
or
x=9
x+1=10
first digit=9
consecutive digit=10