SOLUTION: How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 30% antifreeze to get a mixture that is 70% antifreeze

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Question 618291: How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 30% antifreeze to get a mixture that is 70% antifreeze
Answer by lwsshak3(11628) About Me  (Show Source):
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How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 30% antifreeze to get a mixture that is 70% antifreeze
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let x=gallons of 80% solution to be mixed
x+80=gallons go final 70% mixture
..
80%*x+30%*80=70%*(x+80)
.8x+24=.7x+56
.1x=32
x=320
ans:
gallons of 80% solution to be mixed=320