SOLUTION: how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze

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Question 609319: how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze
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alcohol + alcohol = alcohol
0.80x + 0.10*100 = 0.70(x+100)
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80x + 10*100 = 70x + 70*100
10x = 60*100
x = 600 gallons (amt. of 80% solution needed)
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Cheers,
Stan H.
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