SOLUTION: A chemist is mixing a solution containing 15% bromine with a second solution containing 28% bromine. She wishes to prepare 60 oz. of a solution containing 21% bromine. How much o
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Question 576023: A chemist is mixing a solution containing 15% bromine with a second solution containing 28% bromine. She wishes to prepare 60 oz. of a solution containing 21% bromine. How much of each of the solutions should she use? [Round to the nearest tenth of an ounce.] Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A chemist is mixing a solution containing 15% bromine with a second solution containing 28% bromine. She wishes to prepare 60 oz. of a solution containing 21% bromine. How much of each of the solutions should she use?
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Equation:
0.15x + 0.28(60-x) = 0.21*60
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Multiply thru by 100:
15x + 28*60 - 28x = 21*60
-13x = -7*60
x = (7/13)60
x = 32.3 oz (amt. of 15% solution needed)
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60-x = 27.7 oz (amt. of 28% solution needed)
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Cheers,
Stan H.
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