SOLUTION: Your assistance is greatly appreciated. Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an app

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Question 57311This question is from textbook Elementary and Intermediate algebra
: Your assistance is greatly appreciated.
Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of 40% antifreeze solution. How many quarts of each should she use? This question is from textbook Elementary and Intermediate algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of 40% antifreeze solution. How many quarts of each should she use?
If the total amount of solution is: 20 qts
And we call amount of the pure antifreeze solution: x
Then the rest of the mixture is 40% solution: 20-x
:
Then the amount of antifreeze in pure antifreeze is: 1*x=x
Then the amount of antifreeze in the 40% solution is: .40(20-x)
Then the amoung of antifreeze in the miture of 50% solution is: .50(20)
:
Our problem to solve is:
x+.40(20-x)=.50(20)
x+8-.4x=10
.6x+8=10
.6x+8-8=10-8
.6x=2
.6x/.6=2/.6
x=3.33... qts
The amount of pure alcohol is:x=3.33...qts
The amount of 40% solution is: 20-x=20-3.33...=16.66...pts
Round off where your teacher tells you to.
Happy Calculating!!!