Question 571434: In the lab, Charmaine has two solutions that contain alcohol and is mixing them with each other. She uses 200 milliliters less of Solution A than Solution B. Solution A is 19% alcohol and Solution B is 11% alcohol. How many milliliters of Solution A does she use, if the resulting mixture has 292 milliliters of pure alcohol?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! She uses 200 milliliters less of Solution A than Solution B. Solution A is 19% alcohol and Solution B is 11% alcohol. How many milliliters of Solution A does she use, if the resulting mixture has 292 milliliters of pure alcohol?
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Equations:
A = B-200 ml
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alcohol + alcohol = alcohol
0.19A + 0.11B = 292
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Substitute for "A" and solve for "B":
0.19(B-200) + 0.11B = 292
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Multiply thru by 100:
19B - 3800 +11B = 29200
30B = 33000
B = 1100 ml
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Solve for "A":
A = B - 200
A = 900 ml
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Cheers,
Stan H.
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