SOLUTION: in a chemistry class, 15L of a 13% alchohol solution must be mixed with a 30% solution to get a 15% solution. how many liters of the 30% solution are needed?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: in a chemistry class, 15L of a 13% alchohol solution must be mixed with a 30% solution to get a 15% solution. how many liters of the 30% solution are needed?
Log On
Question 558851: in a chemistry class, 15L of a 13% alchohol solution must be mixed with a 30% solution to get a 15% solution. how many liters of the 30% solution are needed? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Alcohol type I 13 ---------------- 15 liters
alcohol type II 30 ---------------- x liters
Mixture 15 ---------------- 20 + x liters
13*15+30x=15(20 +x)
195+30x =300+15x
30x-15x=300-195
15 x = 105
/ 15
x= 7 liters of alcohol type II
