SOLUTION: How many liters of 20% alcohol solution must be mixed with 60 liters of 70% solution to get a 60% solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many liters of 20% alcohol solution must be mixed with 60 liters of 70% solution to get a 60% solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 549191: How many liters of 20% alcohol solution must be mixed with 60 liters of 70% solution to get a 60% solution?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
--------percent ---------------- quantity
Alcohol I 70 ---------------- 60 L
Alcohol II 20 ---------------- x L
Mixture 60 ---------------- 60 + x L

70*60+20x=60(60+x)
4200 + 20 x =3600+60x
20 x + -60x=3600-4200
-40 x = -600
/ -40
x = 15
15 L of Alcohol II