SOLUTION: Hello can someone please assist me with the correct approach to solving this problem? I would greatly appreciate it. Thanks in advance.
Candy Mixtures - Someone wants to mix som
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Candy Mixtures - Someone wants to mix som
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Question 541055: Hello can someone please assist me with the correct approach to solving this problem? I would greatly appreciate it. Thanks in advance.
Candy Mixtures - Someone wants to mix some candy that is worth 45 cents per pound. Some is worth 80 cents per pound to make 350 lb of a mixture worth 65 cents per pound. How much of each type of candy should be used?
You can put this solution on YOUR website! You need to produce 350 lb of mixture.
x = amount of 45 cent candy
350-x = amount of 80 cent candy
.
45x + 80(350-x) = 65*350
.
45x + 28000 -80x = 22750
.
-35x = -5250
.
x = 150 lb of 45-cent candy
.
350-150 = 200 lb of 80-cent candy
.
This results in 350 lb of candy valued at 65 cents per lb.
.
To check the results...
150*45 = 6750
200*80 = 16000
6750+16000 = 22750
.
65*350 = 22750
.
Done.
You can put this solution on YOUR website! Candy Mixtures - Someone wants to mix some candy that is worth 45 cents per pound. Some is worth 80 cents per pound to make 350 lb of a mixture worth 65 cents per pound. How much of each type of candy should be used?
Suppose we mix x pounds of the 45¢ candy with y pounds of the 80¢ candy.
Then we have two equations, a candy equation and a money equation:
The candy equation comes from this:
+ =
x + y = 350
The money equation comes from
+ =
(45¢)x + (80¢)y = (60¢)(350) or
45x + 80y = 21000
So solve this system of equations:
x + y = 350
45x + 80y = 21000
(If you can't solve that system of equations, post again asking how)
Answer: Mix 200 pounds of the less expensive candy and 150 pounds of the cheaper candy.
Edwin