SOLUTION: How many liters of pure acid must be added to 5L of a solution that is 20% acid to make a solution that is 60% acid? x+0.2 (5)= 0-6 (x=5) x=1= o.6x+3 -0.6x-1-0.6x-1 _________

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Question 540371: How many liters of pure acid must be added to 5L of a solution that is 20% acid to make a solution that is 60% acid?
x+0.2 (5)= 0-6 (x=5)
x=1= o.6x+3
-0.6x-1-0.6x-1
____________________
0.4x=2
______
0.4 0.4
x=5
Does my work look correct?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of pure acid needed
given:
+.2%2A5+=+1+ liter od pure acid in 20% solution
+%28+1+%2B+x+%29+%2F+%28+5+%2B+x+%29+=+.6+
+1+%2B+x+=+.6%2A%28+5+%2B+x+%29+
+1+%2B+x++=+3+%2B+.6x+
+.4x+=+2+
+x+=+5+
5 liters of pure acid is needed
check:
+%28+1+%2B+5+%29+%2F+%28+5+%2B+5+%29+=+.6+
+6+%2F+10+=+.6+
+.6+=+.6+
OK
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I'm not sure how you did it, but this is how
I do all these kind of problems. Same answer.