SOLUTION: How many ounces of 17 % alcohol solution and 39 % alcohol solution must be combined to obtain 88 ounces of 31% solution?

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Question 538171: How many ounces of 17 % alcohol solution and 39 % alcohol solution must be combined to obtain 88 ounces of 31% solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = ounces of 17% solution needed
Let b = ounces of 39% solution needed
given:
+.17a+ = ounces of alcohol in 17% solution
+.39b+ = ounces of alcohol in 39% solution
+.31%2A88+=+27.28+ = ounces of alcohol in final solution
----------------
(1) +a+%2B+b+=+88+
(2) +%28+.17a+%2B+.39b+%29+%2F+88+=+.31+
(2) +.17a+%2B+.39b+=+27.28+
(2) +17a+%2B+39b+=+2728+
Multiply both sides of (1) by +17+
and subtract (1) from (2)
(2) +17a+%2B+39b+=+2728+
(1) +-17a+-+17b+=+-1496+
+22b+=+1232+
+b+=+56+
and, since
(1) +a+%2B+b+=+88+
(1) +a+%2B+56+=+88+
(1) +a+=+32+
32 ounces of 17% solution are needed
56 ounces of 39% solution are needed
check:
(2) +%28+.17a+%2B+.39b+%29+%2F+88+=+.31+
(2) +%28+.17%2A32+%2B+.39%2A56+%29+%2F+88+=+.31+
(2) ++5.44+%2B+21.84+=+.31%2A88+
(2) +27.28+=+27.28+
OK