SOLUTION: Charles is doing an experiment that calls for a 40% solution of copper sulfate. He has 60 mL of a 25% solution. How many milliliters of a 70% solution should Charles add to obtain

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Question 536485: Charles is doing an experiment that calls for a 40% solution of copper sulfate. He has 60 mL of a 25% solution. How many milliliters of a 70% solution should Charles add to obtain the required 40% solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ml of 70% solution needed
given:
+.7x+ = ml of copper sulfate in 70% solution
+.25%2A60+=+15+ ml of copper sulfate in 25% solution
----------------
In words:
( final ml of copper sulfate ) / ( final ml of solution ) = 40%
+%28+.7x+%2B+15+%29+%2F+%28+x+%2B+60+%29+=+.4+
+.7x+%2B+15+=+.4%2A%28+x+%2B+60+%29+
+.7x+%2B+15+=+.4x+%2B+24+
+.3x+=+24+-+15+
+.3x+=+9+
+x+=+30+
30 ml of 70% solution are needed
check:
+%28+.7%2A30+%2B+15+%29+%2F+%28+30+%2B+60+%29+=+.4+
+%28+21+%2B+15+%29+%2F+90+=+.4+
+36+=+.4%2A90+
+36+=+36+
OK